Saturday, February 28, 2009

remainders..........

what are the remainders wn following expressions are divided by 144?
(A)1^5+2^5+3^5+....................44^5+45^5
(B)(1^5)(2^5)(3^5)....................(44^5)(45^5)
(C)1^5,2^5,3^5,....................,44^5,45^5written in a line 2get a huge no.

nd d options are
(a)zero
(b)81
(c)117
(d)45
(e)None of these

6 comments:

monika b said...

m waiting 4 ans...

swati said...

ans for (A) is cmg 81

aashwi verma said...
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aashwi verma said...

a) None of these
b) zero
c) 117 .....not too sure

Unknown said...

b) 0
c) 144=16*9
(111112222233333.......4545454545)
dividing by 9,remainder=0
by 16, (checking last 4 digits 4545) rem. = 1
soTHE REMAINDER IS DEFINITELY 81 SATISFYING FOR 9 = 0
& FOR 16 = 1

ritesh... said...

but mam acc to sol of sfd tere are 6 1's...shudnt there be more than 6?