231.. (a+b+c)^20=[1+(b+c)/a]^20*(a^20) expanding it binomially,we get 21 terms 20 C r(1^r)*(b+c/a)^(20-r) as general term.. we get the terms containing elements as 1+2+3+4+......21 so 231 is the ans.... m i ryt?
How many distinct terms are there in (a+b+c)^20? i got the answer as 231 mam...
now, a+b+c = 20, How many non negative integral solns exist fords equation??? is d answer of dis 63.... and how to correlate both dese questions mam....
5 comments:
231..
(a+b+c)^20=[1+(b+c)/a]^20*(a^20)
expanding it binomially,we get 21 terms
20 C r(1^r)*(b+c/a)^(20-r) as general term..
we get the terms containing elements as
1+2+3+4+......21
so 231 is the ans....
m i ryt?
yeah u r absolutely correct...
solve 1 more qus...
a+b+c = 20, How many non negative integral solns exist fords equation???
can u corelate both dese qustions????
How many distinct terms are there in (a+b+c)^20?
i got the answer as 231 mam...
now, a+b+c = 20, How many non negative integral solns exist fords equation???
is d answer of dis 63....
and how to correlate both dese questions mam....
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