wel,i dnt kno wedr its d ryt solution.. [(32^32)^32]/7 vyl solvin 4 odr smallr numbrs,i found out dat v can get d ans if v keep on dividin d remaindr left aftr successiv divison wid d divisr..so, [(32^32)^32]/7=[(4^32)^32]/7 ;{coz 4 is d rmaindr aftr 32/7} =[4^1024]/7 =[16^512]/7 applyin d sam concpt, [16^512]/7=[2^512]/7 ;{2 is d remaindr aftr 16/7}
now,if v keep n divin d remaindr left wid 7,v gt (2^8)/7=(16^2)/7 =(2^2)/7=4/7 so 4 is d remaindr...
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wel,i dnt kno wedr its d ryt solution..
[(32^32)^32]/7
vyl solvin 4 odr smallr numbrs,i found out dat v can get d ans if v keep on dividin d remaindr left aftr successiv divison wid d divisr..so,
[(32^32)^32]/7=[(4^32)^32]/7 ;{coz 4 is d rmaindr aftr 32/7}
=[4^1024]/7
=[16^512]/7
applyin d sam concpt,
[16^512]/7=[2^512]/7 ;{2 is d remaindr aftr 16/7}
now,if v keep n divin d remaindr left wid 7,v gt
(2^8)/7=(16^2)/7
=(2^2)/7=4/7
so 4 is d remaindr...
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